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без примеровНайдено в 2 словарях

Общая лексика
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disjoint

[dɪs'ʤɔɪnt]

гл.

  1. нарушать структуру, вносить беспорядок

  2. разбирать на составные части

  3. отделять, отсоединять

  4. мед. вывёртывать; вывихивать; смещать

Engineering (En-Ru)

disjoint

разъединять; разобщать

Откройте все бесплатные
тематические словари

Примеры из текстов

Then there is a constant M such that for any finite collection A,, j = 1, 2,..., n, of bounded operators in § which commute with T, and any collection as, j = 1, 2, ..., n, of disjoint Borel sets, we have
Тогда существует такая постоянная М, что для любого конечного набора Ajy j - 1,2, . . ., а, ограниченных операторов в ig, коммутирующих с Т, и любого набора ojy j = 1, 2, . . ., /г, непересекающихся борелевских множеств выполнено неравенство
Dunford, Nelson,Schwartz, Jacob / Linear operators. Part III: Spectral operatorsДанфорд, Н.,Шварц, Дж. / Линейные операторы. Спектральные операторы
Линейные операторы. Спектральные операторы
Данфорд, Н.,Шварц, Дж.
© Перевод на русский язык, "Мир", 1973
Linear operators. Part III: Spectral operators
Dunford, Nelson,Schwartz, Jacob
© 1971, by John Wiley & Sons, Inc., Nelson Dunford and Jacob Schwartz
We ask under what conditions pairwise disjoint transversals with prescribed defects exist.
Спрашивается, при каких условиях существуют попарно непересекающиеся трансверсали с предписанными дефектами.
Aigner, Martin / Combinatorial TheoryАйгнер, Мартин / Комбинаторная теория
Комбинаторная теория
Айгнер, Мартин
© 1979 by Springer-Verlag New York Inc.
© Перевод на русский язык, «Мир», 1982
Combinatorial Theory
Aigner, Martin
© Springer-Verlag Berlin Heidelberg 1997
The variables of Fi and F2 are disjoint, except for those variables that appear in E.
Переменные в формулах Fi и F2 различны, за исключением присутствующих в Е.
Hopcroft, John,Motwani, Rajeev,Ullman, Jeffrey / Introduction to automata theory, languages, and computationХопкрофт, Джон,Мотвани, Раджив,Ульман, Джеффри / Введение в теорию автоматов, языков и вычислений
Введение в теорию автоматов, языков и вычислений
Хопкрофт, Джон,Мотвани, Раджив,Ульман, Джеффри
© Издательский дом "Вильямс", 2002
© Addison-Wesley Publishing Company, Inc. 2001
Introduction to automata theory, languages, and computation
Hopcroft, John,Motwani, Rajeev,Ullman, Jeffrey
© 2001 by Addison-Wesley
It is clear that the sets ap(A). ac(A), and ar(A) are disjoint and a(A) =op(A) u ac(A) v °r(A).
Очевидно, множества ор (Л), ас (Л) и аг (Л) не пересекаются и а (Л) = ар (Л) U ас (Л) U оТ (Л).
Dunford, Nelson,Schwartz, Jacob / Linear operators. Part III: Spectral operatorsДанфорд, Н.,Шварц, Дж. / Линейные операторы. Спектральные операторы
Линейные операторы. Спектральные операторы
Данфорд, Н.,Шварц, Дж.
© Перевод на русский язык, "Мир", 1973
Linear operators. Part III: Spectral operators
Dunford, Nelson,Schwartz, Jacob
© 1971, by John Wiley & Sons, Inc., Nelson Dunford and Jacob Schwartz
Construct a tree with disjoint center and centroid, each having two points.
Построить дерево с непересекающимися центром и центроидом, каждый из которых состоит из двух вершин.
Harary, Frank / Graph TheoryХарари, Фрэнк / Теория графов
Теория графов
Харари, Фрэнк
© Едиториал УРСС. 2003
Graph Theory
Harary, Frank
© 1969 by Addison-Wesley Publishing Company, Inc.
Let a(x) and a(y) be disjoint.
Предположим, что спектры а (х) и о (у) не пересекаются.
Dunford, Nelson,Schwartz, Jacob / Linear operators. Part III: Spectral operatorsДанфорд, Н.,Шварц, Дж. / Линейные операторы. Спектральные операторы
Линейные операторы. Спектральные операторы
Данфорд, Н.,Шварц, Дж.
© Перевод на русский язык, "Мир", 1973
Linear operators. Part III: Spectral operators
Dunford, Nelson,Schwartz, Jacob
© 1971, by John Wiley & Sons, Inc., Nelson Dunford and Jacob Schwartz
Show that a subset of X is constructible if and only if it can be written as a finite disjoint union of locally closed subsets.
Показать, что подмножество в X тогда и только тогда конструктивно, когда оно может быть представлено как конечное объединение локально замкнутых подмножеств.
Hartshorne, Robin / Algebraic GeometryХартсхорн, Р. / Алгебраическая Геометрия
Алгебраическая Геометрия
Хартсхорн, Р.
© Перевод на русский язык, «Мир», 1981
Algebraic Geometry
Hartshorne, Robin
© 1977 Springer-Verlag New York Inc.
Now from Zorn's lemma we obtain a maximal family Jy of disjoint elements of B each having uniform multiplicity.
Применяя лемму Цорна, мы получаем максимальное семейство % попарно дизъюнктных элементов из B, каждый из которых обладает однородной кратностью.
Dunford, Nelson,Schwartz, Jacob / Linear operators. Part III: Spectral operatorsДанфорд, Н.,Шварц, Дж. / Линейные операторы. Спектральные операторы
Линейные операторы. Спектральные операторы
Данфорд, Н.,Шварц, Дж.
© Перевод на русский язык, "Мир", 1973
Linear operators. Part III: Spectral operators
Dunford, Nelson,Schwartz, Jacob
© 1971, by John Wiley & Sons, Inc., Nelson Dunford and Jacob Schwartz
A disjoint branching rule.
Правило исключающего ветвления.
Christofides, Nicos / Graph Theory. An Algorithmic ApproachКристофидес, Никос / Теория графов. Алгоритмический подход
Теория графов. Алгоритмический подход
Кристофидес, Никос
© 1975 by Academic Press Inc. (London)Ltd.
© Перевод на русский язык, «Мир», 1978
Graph Theory. An Algorithmic Approach
Christofides, Nicos
© 1975 by ACADEMIC PRESS INC. (LONDON) LTD.
For we may consider families of disjoint projections in B each member of which is bounded by an Ea, and order these families by inclusion.
Действительно, рассмотрим семейства попарно дизъюнктных проекторов из В, каждый член которых мажорируется некоторым проектором Еа, и упорядочим эти семейства по включению.
Dunford, Nelson,Schwartz, Jacob / Linear operators. Part III: Spectral operatorsДанфорд, Н.,Шварц, Дж. / Линейные операторы. Спектральные операторы
Линейные операторы. Спектральные операторы
Данфорд, Н.,Шварц, Дж.
© Перевод на русский язык, "Мир", 1973
Linear operators. Part III: Spectral operators
Dunford, Nelson,Schwartz, Jacob
© 1971, by John Wiley & Sons, Inc., Nelson Dunford and Jacob Schwartz
If a graph is 2-factorable, then each factor must be a union of disjoint cycles.
Если граф 2-факторизуем, то каждый его фактор должен быть объединением непересекающихся (по вершинам) циклов.
Harary, Frank / Graph TheoryХарари, Фрэнк / Теория графов
Теория графов
Харари, Фрэнк
© Едиториал УРСС. 2003
Graph Theory
Harary, Frank
© 1969 by Addison-Wesley Publishing Company, Inc.
By Zorn's lemma we can find a maximal family of disjoint carrier projections Ey bounded by E.
По лемме Цорна существует максимальное семейство попарно дизъюнктных проекторов-носителей Еу, мажорируемых проектором Е.
Dunford, Nelson,Schwartz, Jacob / Linear operators. Part III: Spectral operatorsДанфорд, Н.,Шварц, Дж. / Линейные операторы. Спектральные операторы
Линейные операторы. Спектральные операторы
Данфорд, Н.,Шварц, Дж.
© Перевод на русский язык, "Мир", 1973
Linear operators. Part III: Spectral operators
Dunford, Nelson,Schwartz, Jacob
© 1971, by John Wiley & Sons, Inc., Nelson Dunford and Jacob Schwartz
As this table and the symbol table occupy disjoint areas, we can tell to which table a pointer points.
Поскольку эта таблица и таблица символов занимают непересекающиеся области, мы можем определить, на запись какой таблицы указывает указатель.
Aho, Alfred V.,Sethi, Ravi,Ullman, Jeffrey / Compilers: Principles, Techniques, and ToolsАхо, Альфред В.,Ульман, Джеффри,Сети, Рави / Компиляторы: принципы, технологии, инструменты
Компиляторы: принципы, технологии, инструменты
Ахо, Альфред В.,Ульман, Джеффри,Сети, Рави
© Addison-Wesley Publishing Company, Inc., 1985
© 2001
© Издательский дом "Вильямс", 2001
Compilers: Principles, Techniques, and Tools
Aho, Alfred V.,Sethi, Ravi,Ullman, Jeffrey
© 2001 by PEARSON EDUCATION NORTH ASIA LIMITED and PEOPLE'S POSTS & TELECOMMUNICATIONS PUBLISHING HOUSE
© 1986
Her brain felt disjointed, full of unresolved worry, plagued by loose ends of uncertainty and fear.
Словно кто-то устроил кавардак в ее голове, забив ее до отказа непонятным беспокойством и загромоздив проходы болтающимися без дела сомнениями и страхами.
Westerfeld, Scott / Touching DarknessВестерфельд, Скотт / Прикосновение Тьмы
Прикосновение Тьмы
Вестерфельд, Скотт
© 2004 by Alloy Entertainment and Scott David Westerfield
© Перевод.Е. Секисова, 2006
© Издание на русском языке. ООО "Издательство "Эксмо", 2009
Touching Darkness
Westerfeld, Scott
© 2004 by Alloy Entertainment and Scott David Westerfield
Hopelessly he turned back into Broadway again and slopped onward and away, begging, crying, losing track of his thoughts, one after another, as a mind decayed and disjointed is wont to do.
С безнадежным видом поплелся он по Бродвею, плаксиво прося по дороге милостыню и каждый раз забывая, о чем он только что думал.
Dreiser, Theodore / Sister CarrieДрайзер, Теодор / Сестра Керри
Сестра Керри
Драйзер, Теодор
© Издательство "Правда", 1986
Sister Carrie
Dreiser, Theodore
© Nov. 8, 1900 No. A27641 by Doubleday, Page & Co.
© renewed by Theodore Dreiser as Author Nov. 17, 1927 No. R42188

Добавить в мой словарь

disjoint1/5
dɪs'ʤɔɪntГлаголнарушать структуру; вносить беспорядок

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Словосочетания

code disjoint circuit
схема, развязанная по кодам
disjoint balls
непересекающиеся шары
disjoint closures
непересекающиеся замыкания
disjoint coalitions
непересекающиеся коалиции
disjoint covering
дизъюнктное покрытие
disjoint dihedron
расчлененный диэдр
disjoint disks
непересекающиеся диски
disjoint elements
дизъюнктивные элементы
disjoint events
независимые события
disjoint events
несовместные события
disjoint figure
расчлененное изображение
disjoint homomorphism
разделенный гомоморфизм
disjoint ideal
дизъюнктный идеал
disjoint intervals
непересекающиеся интервалы
disjoint neighborhoods
непересекающиеся окрестности

Формы слова

disjoint

verb
Basic forms
Pastdisjointed
Imperativedisjoint
Present Participle (Participle I)disjointing
Past Participle (Participle II)disjointed
Present Indefinite, Active Voice
I disjointwe disjoint
you disjointyou disjoint
he/she/it disjointsthey disjoint
Present Continuous, Active Voice
I am disjointingwe are disjointing
you are disjointingyou are disjointing
he/she/it is disjointingthey are disjointing
Present Perfect, Active Voice
I have disjointedwe have disjointed
you have disjointedyou have disjointed
he/she/it has disjointedthey have disjointed
Present Perfect Continuous, Active Voice
I have been disjointingwe have been disjointing
you have been disjointingyou have been disjointing
he/she/it has been disjointingthey have been disjointing
Past Indefinite, Active Voice
I disjointedwe disjointed
you disjointedyou disjointed
he/she/it disjointedthey disjointed
Past Continuous, Active Voice
I was disjointingwe were disjointing
you were disjointingyou were disjointing
he/she/it was disjointingthey were disjointing
Past Perfect, Active Voice
I had disjointedwe had disjointed
you had disjointedyou had disjointed
he/she/it had disjointedthey had disjointed
Past Perfect Continuous, Active Voice
I had been disjointingwe had been disjointing
you had been disjointingyou had been disjointing
he/she/it had been disjointingthey had been disjointing
Future Indefinite, Active Voice
I shall/will disjointwe shall/will disjoint
you will disjointyou will disjoint
he/she/it will disjointthey will disjoint
Future Continuous, Active Voice
I shall/will be disjointingwe shall/will be disjointing
you will be disjointingyou will be disjointing
he/she/it will be disjointingthey will be disjointing
Future Perfect, Active Voice
I shall/will have disjointedwe shall/will have disjointed
you will have disjointedyou will have disjointed
he/she/it will have disjointedthey will have disjointed
Future Perfect Continuous, Active Voice
I shall/will have been disjointingwe shall/will have been disjointing
you will have been disjointingyou will have been disjointing
he/she/it will have been disjointingthey will have been disjointing
Future in the Past Indefinite, Active Voice
I should/would disjointwe should/would disjoint
you would disjointyou would disjoint
he/she/it would disjointthey would disjoint
Future in the Past Continuous, Active Voice
I should/would be disjointingwe should/would be disjointing
you would be disjointingyou would be disjointing
he/she/it would be disjointingthey would be disjointing
Future in the Past Perfect, Active Voice
I should/would have disjointedwe should/would have disjointed
you would have disjointedyou would have disjointed
he/she/it would have disjointedthey would have disjointed
Future in the Past Perfect Continuous, Active Voice
I should/would have been disjointingwe should/would have been disjointing
you would have been disjointingyou would have been disjointing
he/she/it would have been disjointingthey would have been disjointing
Present Indefinite, Passive Voice
I am disjointedwe are disjointed
you are disjointedyou are disjointed
he/she/it is disjointedthey are disjointed
Present Continuous, Passive Voice
I am being disjointedwe are being disjointed
you are being disjointedyou are being disjointed
he/she/it is being disjointedthey are being disjointed
Present Perfect, Passive Voice
I have been disjointedwe have been disjointed
you have been disjointedyou have been disjointed
he/she/it has been disjointedthey have been disjointed
Past Indefinite, Passive Voice
I was disjointedwe were disjointed
you were disjointedyou were disjointed
he/she/it was disjointedthey were disjointed
Past Continuous, Passive Voice
I was being disjointedwe were being disjointed
you were being disjointedyou were being disjointed
he/she/it was being disjointedthey were being disjointed
Past Perfect, Passive Voice
I had been disjointedwe had been disjointed
you had been disjointedyou had been disjointed
he/she/it had been disjointedthey had been disjointed
Future Indefinite, Passive Voice
I shall/will be disjointedwe shall/will be disjointed
you will be disjointedyou will be disjointed
he/she/it will be disjointedthey will be disjointed
Future Perfect, Passive Voice
I shall/will have been disjointedwe shall/will have been disjointed
you will have been disjointedyou will have been disjointed
he/she/it will have been disjointedthey will have been disjointed